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Question

An ideal heat engine working between temperatures TH and TL has an efficiency η . If both the temperatures are raised by 100 K each, the new efficiency of the heat engine will be :

A
equal to η
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B
greater than η
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C
less than η
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D
greater or less than η depending upon the nature of the working substance.
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Solution

The correct option is C less than η
The efficiency of a heat engine is given by,
η=THTLTH
Increasing both the temperatures by 100,
η=THTLTH+100
Thus, the efficiency will effectively decrease.

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