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An ideal mona...

Question

An ideal monatomic gas expands to twice its volume. If the process is isothermal, the magnitude of work done by the gas is $W_{i}$ . If the process is adiabatic, the magnitude of work done by the gas is $W_{a}$ . Which of the following is true?

W_{i} = W_{a} > 0

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W_{i} > W_{a} = 0

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W_{i} > W_{a} > 0

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W_{a} = W_{i} = 0

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Solution

The correct option is C $W_{i} > W_{a} > 0$
From the image we can conclude that:
Isothermal line is always higher than the adiabatic line and they both end at the same volume
The area under the isothermal line is bigger than the adiabatic $∴ W_{a} < W_{i}$
Since gas is going work $W_{i} > W_{a} > 0$ .

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