Given Data:
At constant pressure heat supplied, Q=80J
For ideal monoatomic gas, Cv=3R2
Step 1: Increase in internal energy:
Work done, W=PΔV=nRΔT
Change in internal energy, W=PΔV=nRΔT
By first law of thermodynamics;
Q=W+ΔU
80=nRΔT+32nRΔT
80=5nRΔT2⟹nRΔT=32
We know.
ΔU=nCvΔT
ΔU=n(32R)ΔT
ΔU=32nRΔT⟹ΔU=32×32=48J
So,
Increase in internal energy, =48J