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Gibb's Energy and Nernst Equation

An ideal mono...

Question

An ideal monoatomic gas is initially in state –1 with pressure $P_{1} = 20$ atm and volume $V_{1} = 1500 c m^{3}$ . It is then taken to state-2 with pressure $P_{2} = 1.5 P_{1}$ and volume $V_{2} = 2 V_{1}$ . The change in internal energy from state-1 to state-2 is equal to:

A

2000 J

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B

3000 J

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C

6000 J

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D

9000 J

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Solution

The correct option is D 9000 J
$Δ U = \frac{f}{2} n R Δ T = \frac{f}{2} (P_{2} V_{2} - P_{1} V_{1})$

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