Question

An ideal monoatomic gas is taken round the cycle $ABCDA$ as shown in following $P-V$ diagram. The work done during the cycle is

• A. $PV$
• B. $2PV$
• C. $4PV$
• D. $Zero$

Answer 1

Answer: (A)

$PV$

$\text{Solution}:$

Work done during the cycle = area enclosed in the curve =(2P−P)(2V−V)=PV

$\text{Hence A is the correct option}$