Question

An ideal monoatomic gas is taken through cycle $A\to B\to C\to A$. What is the heat change during the cycle $A\to B\to C\to A$?

• A. $=\frac{-4P_0{V}_0}{2}$
• B. $-6P_0{V}_0$
• C. $9P_0{V}_0$
• D. $2P_0{V}_0$

Answer 1

The correct option is A $=\frac{-4P_0{V}_0}{2}$

An ideal monoatomic gas is taken through cycle $A\to B\to C\to A$. The work done by the gas during the cycle $A\to B\to C\to A$ is $\frac{\Delta P\times \Delta V}{2}=\frac{(2P_0-P_0)(6V_0-2V_0)}{2}=\frac{4P_0{V}_0}{2}$. But the heat change $q=-W=-\frac{4P_0{V}_0}{2}$