Question

An ideal p-n junction diode can withstand currents up to $10$mA under forward bias. The diode has a potential difference of $0.5$V across it which is assumed:

Answer 1

let the voltage of battery be $V$.

Potential difference of the diode is 0.5 V.

$\because V=IR$,

$I=\frac{V}{R}$--------- (1)

Voltage over the resistor be V-0.5

(1)=> $I=\frac{V}{R}=\frac{V-0.5}{R}A$