An ideal pulley system can lift a load of 1500 N by an effort of 300 N. The velocity ratio of the system is:

3

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2

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5

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6

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Solution

The correct option is C $5$
Given,
Load = 1500 N
Effort = 300 N

M.A. $= \frac{Load}{Effort} = \frac{1500}{300} = 5$

Efficiency = $\frac{M.A.}{V.R.}$

For an ideal pulley, the efficiency is $100 %$ or $1$ .
So, its velocity ratio $V.R.$ = $5$

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An ideal pulley system can lift a load of 1500 N by an effort of 300 N. The velocity ratio of the system is:

The correct option is C 5Given, Load = 1500 N Effort = 300 N M.A. =LoadEffort=1500300=5 Efficiency = M.A.V.R. For an ideal pulley, the efficiency is 100% or 1. So, its velocity ratio V.R. = 5

The correct option is C $5$
Given,
Load = 1500 N
Effort = 300 N

M.A. $= \frac{Load}{Effort} = \frac{1500}{300} = 5$

Efficiency = $\frac{M.A.}{V.R.}$

For an ideal pulley, the efficiency is $100 %$ or $1$ .
So, its velocity ratio $V.R.$ = $5$