An ideal solenoid is placed as shown- V A - V B will be-A- 72 VB- -72 VC- -12 VD- -12 V

The correct option is D 12 Ve=|Ldi/dt| e=|Ldi/dt|=|6× ( 2)|=12 V But accroding to lenz's law, induced emf will oppose current flow , V_B gt; V_A . Therefor ...

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Standard XII

Physics

Alternating Current Applied to an Inductor

An ideal sole...

Question

An ideal solenoid is placed as shown. $V_{A} - V_{B}$ will be,

72 V

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-72 V

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+12 V

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-12 V

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Solution

The correct option is D -12 V
$e = ∣ ∣ L \frac{d i}{d t} ∣ ∣$
$e = ∣ ∣ L \frac{d i}{d t} ∣ ∣ = | 6 \times (- 2) | = 12 V$
But accroding to lenz's law, induced emf will oppose current flow , $V_{B} > V_{A}$ . Therefore -12V is correct answer.

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An ideal solenoid is placed as shown. VA−VB will be,

The correct option is D -12 Ve=∣∣Ldidt∣∣ e=∣∣Ldidt∣∣=|6×(−2)|=12 V But accroding to lenz's law, induced emf will oppose current flow , VB>VA . Therefore -12V is correct answer.

An ideal solenoid is placed as shown. $V_{A} - V_{B}$ will be,

The correct option is D -12 V
$e = ∣ ∣ L \frac{d i}{d t} ∣ ∣$
$e = ∣ ∣ L \frac{d i}{d t} ∣ ∣ = | 6 \times (- 2) | = 12 V$
But accroding to lenz's law, induced emf will oppose current flow , $V_{B} > V_{A}$ . Therefore -12V is correct answer.