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Question

An ideal solution of benzene and toluene boils at 1 atm pressure at 90 C. At 90 C benzene has a vapour pressure of 1022 mm of Hg and toluene has a vapour pressure of 406 mm of Hg. The mole fraction of benzene in the solution:

A
0.360
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B
0.640
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C
0.575
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D
0.425
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Solution

The correct option is C 0.575
Given,
Vapour pressure of pure benzene, P0B=1022 mm of Hg
Vapour pressure of pure toluene , P0T=406 mm of Hg

We know,
P0BχB+P0TχT=Ptotal

1022 χB+406(1χB)=1atm=760 mm of Hg

χB=0.575

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