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Mole Fraction

An ideal solu...

Question

An ideal solution was obtained by mixing methanol and ethanol. If the partial vapour pressure of methanol and ethanole are 2.619 kPa and 4.556 kPa, respectively, the composition of vapour (in terms of mole fraction) will be

A

0.635 MeOH, 0.365 EtOH

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B

0.365 MeOH, 0.635 EtOH

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C

0.574 MeOH, 0.326 EtOH

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D

0.173 MeOH, 0.827 EtOH

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Solution

The correct option is B 0.365 MeOH, 0.635 EtOH
$P_{E t O H} = P^{\circ} \times$ Mole fraction of EtOH in liquid phase
$= P_{T} \times$ Mole fraction of EtOH in vapour phase
Thus, mole fraction of EtOH in vapour phase
$= \frac{P^{'}}{P_{T}} = \frac{4.556}{4.556 + 2.619} = 0.635$

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