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Question

An ideal spring fixed from left end, of spring constant 5 N/m is attached to a block and is stretched to a distance 3m from relaxed position towards right end. If the block compresses to half of its initial extension after release, what is the average frictional force?

A
4.25 N
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B
3.75 N
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C
2.75 N
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D
2.5 N
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Solution

The correct option is B 3.75 N
k= 5 N/m, x1=3m
every v1=12kx2=22.5 joule

compresses =32=1.5m=x2
every =v2=12kx2=1.125×5
=5625 joule
lose = 22.5-5.625 = 16.875 joule
distance = 3m right +1.5 (compression)
(in coming to real x)
=4.5
Force ×4.5=16.875 joule force =16.8754.5=3.75N


1186335_1362570_ans_375b14e2e5104e43bf24d27b1cedbe8b.jpg

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