An ideal spring having force constant k is suspended from the rigid support and a block of mass M is attached to its lower end. The mass is released from the natural length of the spring. Then the maximum extension in the spring is
A
4Mgk
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B
2Mgk
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C
Mgk
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D
Mg2k
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Solution
The correct option is B2Mgk Potential energy =12kx2=Mgx⇒x=2Mgk