An ideal spring of spring constant k is hung from a ceiling and a block of mass M is attached to its lower end. When the mass is released, calculate the maximum extension of the spring. ans :-x = 2Mg/k

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Dear Student,

$f i r s t t h e b l o c k a c c e l e r a t e a n d t h e n d e a c e l e r a t e . l e t t h e m a x i m u m e x t e n s i o n b e x c o n s e r v e t h e e n e r g y . t h e l o s i n p o t e n t i a l e n e r g y g o t s t o r e i n t h e e l a s t i c e n r g y a t m a x i m u m e x t e n s i o n a n d K E = 0 \frac{k x^{2}}{2} = m g x x = \frac{2 m g}{k} R e g a r d s$

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An ideal spring of spring constant k is hung from a ceiling and a block of mass M is attached to its lower end. When the mass is released, calculate the maximum extension of the spring. ans :-x = 2Mg/k​

Dear Student, first the block accelerate and then deacelerate.let the maximum extension be xconserve the energy .the los in potential energy got store in the elastic enrgy at maximum extension and KE=0kx22=mgxx=2mgkRegards

An ideal spring of spring constant k is hung from a ceiling and a block of mass M is attached to its lower end. When the mass is released, calculate the maximum extension of the spring. ans :-x = 2Mg/k