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Question

An ideal system operating with n moles of an ideal monatomic gas performs the cycle shown in the PV diagram to the right. All parts of the cycle are carried out slowly and reversibly. Starting at state a, where its volume and pressure are (V0,p0), the gas undergoes an isothermal expansion until it reaches state b where its volume and pressure are (8V0,p0/8). In process bc the gas is cooled at constant volume to (8V0,p0/32). Process ca is an adiabatic compression back to state a.

Select incorrect statement:

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A
ab, there is no change in internal energy of gas
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B
ca, there is no change in entropy of gas
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C
bc, there is no work done by gas
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D
abca, there is work done by gas in cyclic process
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Solution

The correct options are
B ca, there is no change in entropy of gas
D abca, there is work done by gas in cyclic process
In the P vs V diagram the work done is area under the curve.
  1. The work done for the path a to b is positive (let say W1). (volume is increasing) . the isothermal process, i.e. internal energy is not equal to 0.
  2. The work done for path b to c is 0. (no change in volume).
  3. The work done for path c to a is negative.(say W2) (volume decreasing). entropy change is negative.
Total work done W1+0W2
Area under the curve ab > area under the curve c to a
Work done =W1W2 positive value.

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