An ideal transformer has a 150 primary turns and 750 secondary turns . The primary is connected to a 240 V, 50 Hz source. The secondary winding supplies a load of 4 A at a lagging (pf) of 0.8. The power supplied to load is____ W.
3840

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Solution

The correct option is A 3840
$Turns ratio, = \frac{150}{750} = 0.2$

$I_{1} = \frac{I_{2}}{a} = \frac{4}{0.2} = 20 A$

$V_{2} = \frac{V_{1}}{a} = \frac{240}{0.2} = 1200 V$

$Thus, the power supplied to load is$

$P_{L} = V_{2} I_{2} cos θ = 1200 \times 4 \times 0.8 = 3840 W$

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An ideal transformer has a 150 primary turns and 750 secondary turns . The primary is connected to a 240 V, 50 Hz source. The secondary winding supplies a load of 4 A at a lagging (pf) of 0.8. The power supplied to load is____ W.3840

The correct option is A 3840Turns ratio, =150750=0.2 I1=I2a=40.2=20A V2=V1a=2400.2=1200V Thus, the power supplied to load is PL=V2I2cosθ=1200×4×0.8=3840W

An ideal transformer has a 150 primary turns and 750 secondary turns . The primary is connected to a 240 V, 50 Hz source. The secondary winding supplies a load of 4 A at a lagging (pf) of 0.8. The power supplied to load is____ W.
3840

The correct option is A 3840
$Turns ratio, = \frac{150}{750} = 0.2$

$I_{1} = \frac{I_{2}}{a} = \frac{4}{0.2} = 20 A$

$V_{2} = \frac{V_{1}}{a} = \frac{240}{0.2} = 1200 V$

$Thus, the power supplied to load is$

$P_{L} = V_{2} I_{2} cos θ = 1200 \times 4 \times 0.8 = 3840 W$