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Question

An identical liquid is flowing in a tube A of small variable cross-section Tube 1, Tube 2 and Tube 3 is connected at point 1, 2 and 3 respectively as shown Let h1,h2andh3 are the final heights of liquid in tube 1, 2 and 3 respectively and v1,v2andv3 are the velocity of the liquid at cross-section 1, 2 and 3 respectively Match the quantities in List I and List II

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Solution

As the area of cross-section increases, velocity decreases, and the pressure increase. Therefore, the h1 is greater than h3 and h2 is less than h3.
As the area of cross-section of the part 1 is large so it has the least velocity and the velocity is maximum for part 2 since its area of cross-section is least.
So, v2>v3>v1

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