An illuminated object is placed at a distance of 20 cm from a converging lens of focal length 15 cm. The image obtained on the screen is : (a) upright and magnified (b) inverted and magnified (c) inverted and diminished (d) upright and diminished

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Solution

(b) inverted and magnified
because the object is placed in between the focal point and 2F and so the image is formed beyond 2F and hence it is magnified and inverted\

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10 c m

.
(a)

8 c m

(b)

15 c m

(c)

20 c m

(d)

25 c m .

Which position of the object will produce ..............
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iv) an image of same size as the object ?

Justify your answer in each case.

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(2) real, erect and magnified
(3) real, inverted and diminished
(4) virtual, inverted and diminished

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(a) virtual, inverted, and diminished

(b) virtual, upright, and diminished

(d) virtual, upright, and enlarged.

An object AB is placed between 2F₁ and F₁ on the principal axis of a convex lens as shown in the diagram:

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An illuminated object is placed at a distance of 20 cm from a converging lens of focal length 15 cm. The image obtained on the screen is : (a) upright and magnified (b) inverted and magnified (c) inverted and diminished (d) upright and diminished

(b) inverted and magnified because the object is placed in between the focal point and 2F and so the image is formed beyond 2F and hence it is magnified and inverted\

(b) inverted and magnified
because the object is placed in between the focal point and 2F and so the image is formed beyond 2F and hence it is magnified and inverted\