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Electric Field Due to a Dipole at a General Point in Space

An imaginary ...

Question

An imaginary truncated cone is placed in uniform electric field E as shown in the figure. Then total flux linked with cone is

एक काल्पनिक रूंडित शंकु को एकसमान विद्युत क्षेत्र E में चित्रानुसार रखा जाता है, तब शंकु से सम्बद्ध कुल फ्लक्स है

A

Positive

धनात्मक

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B

Negative

ऋणात्मक

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C

Zero

शून्य

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D

Non-zero

अ-शून्य

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Solution

The correct option is C Zero

शून्य
Solution

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Similar questions

Q. A point charge Q is placed at the center of base of a right-angled cone. Total electric flux passing through the curved surface of cone is

एक बिंदु आवेश Q को एक समकोणीय शंकु के आधार के केन्द्र पर रखा गया है। शंकु के वक्राकार पृष्ठ से गुजरने वाला कुल विद्युत फ्लक्स है

Q. A point charge +Q is placed in between two semi-infinite planes, as shown. Total electric flux passing through these two planes, is

एक बिन्दु आवेश +Q को दर्शाए अनुसार दो साम्यनंत तलों के मध्य में रखा जाता है। इन दोनों तलों से गुजरने वाला कुल विद्युत फ्लक्स है

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एक बिन्दु आवेश Q को दर्शाए अनुसार एक घन की किसी एक भुजा पर रखा गया है। इस घन से गुजरने वाला कुल विद्युत फ्लक्स है

Q

is placed inside cone as shown in figure such that

θ = 60^{\circ}

. Flux of electric field associated with curved surface of cone is.

Q. An electric dipole having dipole moment

\to p = (3^i -^j) mC m

is placed in a uniform electric field

\to E = (2^i + 3^j) \times 10^{3} N C^{- 1}

. Then

द्विध्रुव आघूर्ण

\to p = (3^i -^j) mC m

वाले एक विद्युत द्विध्रुव को एकसमान विद्युत क्षेत्र

\to E = (2^i + 3^j) \times 10^{3} N C^{- 1}

में रखा जाता है। तब

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Electric Field Due to a Dipole at a General Point in Space

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