An imaginery force F - B-V given as the cross product of vector B Force field and V velocity- Then the work done by the force is

Work done = F . ds dsdt = V ⇒V.dt = ds Work done = (B×V). (V.dt) = 0 nbsp; Because B×V is always perpendicular to V and the dot product of two mutually perpen ...

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Standard XIII

Physics

Zero Work

An imaginery ...

Question

An imaginery force $\to F = \to B \times \to V$ given as the cross product of vector $\to B$ (Force field) and $\to V$ (velocity). Then the work done by the force is

Always greater than zero

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Always equal to zero

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Always less than zero

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Can have any finite value

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Solution

The correct option is B Always equal to zero
Work done $= \to F . \to d s$
$\frac{\to d s}{d t} = \to V \Rightarrow \to V . d t = \to d s$
Work done = $(\to B \times \to V) . (\to V . d t) = 0$
Because $\to B \times \to V$ is always perpendicular to $\to V$ and the dot product of two mutually perpendicular vectors is always zero.

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An imaginery force →F=→B×→V given as the cross product of vector →B (Force field) and →V (velocity). Then the work done by the force is

The correct option is B Always equal to zero Work done =→F.→ds →dsdt=→V⇒→V.dt=→ds Work done = (→B×→V).(→V.dt)=0 Because →B×→V is always perpendicular to →V and the dot product of two mutually perpendicular vectors is always zero.

An imaginery force $\to F = \to B \times \to V$ given as the cross product of vector $\to B$ (Force field) and $\to V$ (velocity). Then the work done by the force is