Question

An impulse $I$ is applied at the end of a uniform rod of mass $m$. Then:

• A. $KE$ of translation of the rod is $\frac{I^2}{2m}$
• B. $KE$ of translation of the rod is $\frac{I^2}{6m}$
• C. $KE$ of translation of the rod is $\frac{3I^2}{2m}$
• D. $KE$ of the rod is $\frac{2I^2}{m}$

Answer 1

The correct option is A $KE$ of translation of the rod is $\frac{I^2}{2m}$

$KE=\frac{m{v}^2}{2}$

$I=mv$

therefore $KE=\frac{I^2}{2m}$