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Standard XII

Physics

Angular Momentum

An impulse is...

Question

An impulse is applied on a rod at a distance 'y' away from centre C as shown in figure. Rod is kept on frictionless horizontal surface. For what 'y' velocity of end A is zero just after impact?

\frac{L}{4}

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\frac{L}{2}

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\frac{L}{6}

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\frac{2 L}{5}

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Solution

The correct option is C $\frac{L}{6}$

J=mv

Jy= $\frac{m L^{2}}{12} w$

$V_{A} = \frac{L}{2} w - v = 0 \Rightarrow v = \frac{L}{2} w$

$\frac{J}{m} = \frac{L}{2} \times \frac{12 J y}{m L^{2}} \Rightarrow y = \frac{L}{6}$

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An impulse is applied on a rod at a distance 'y' away from centre C as shown in figure. Rod is kept on frictionless horizontal surface. For what 'y' velocity of end A is zero just after impact?

The correct option is C L6 J=mv Jy=mL212w VA=L2w−v=0⇒v=L2w Jm=L2×12 JymL2⇒y=L6

The correct option is C $\frac{L}{6}$

J=mv

Jy= $\frac{m L^{2}}{12} w$

$V_{A} = \frac{L}{2} w - v = 0 \Rightarrow v = \frac{L}{2} w$

$\frac{J}{m} = \frac{L}{2} \times \frac{12 J y}{m L^{2}} \Rightarrow y = \frac{L}{6}$