Question

An inclined plane is moving towards right with an acceleration of $5m{s}^{-2}$ as shown in the figure. Find force in newton which block of mass $5kg$ exerts on the inclined plane. (All surfaces are smooth)

• A. $130$
• B. $55$
• C. $32.5$
• D. $90$

Answer 1

Answer: (B)

$55$

In the frame of wedge, there will be pseudo-force in negative $x-direction$ on $5kg$ block.
And in the frame of wedge, there will be $0$ resultant force on the block along the common normal.
Applying newton's second law on that block will give,
$N=m\times g\times cos{37}^{\circ }+m\times 5\times sin{37}^{\circ }=40+15=55N$