Question

An inclined wedge is having the length of $10meters$ and vertical height $6meters$. A block of mass $2kg$ is placed on the wedge. Calculate the net force felt by block :

(Assume wedge surface is frictionless)

• A. $5N$
• B. $12N$
• C. $15N$
• D. $20N$
• E. 30 N$

Answer 1

Answer: (B)

$12N$

Let the angle of inclination of the wedge be $\theta$.

Thus $sin\theta =\frac{6}{10}=\frac{3}{5}$

The net force acting on the block is $mgsin\theta =2\times 10\times \frac{3}{5}N=12N$