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Question

An incomplete distribution is given below:
Variable
Frequency
1020
12
2030
30
3040
f1
4050
65
5060
f2
6070
25
7080
18
If median value is 46 and the total number of items is 230.
Find the missing frequencies f1 and f2.

A
40 & 46
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B
34 & 46
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C
37 & 50
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D
51 & 46
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Solution

The correct option is B 34 & 46
Forcontinuousdata,median=L+(N2Cf)×HWhereN=TotalcumulativefrequencyL=lowerlimitofthemedianclassInterval;MedianClass=theclassinterval
havingcumulativefreqN2liesC=cumulativefrequencyoftheclassintervaljustbeforethemedianclassintervalf=frequencyofthemedianclassinterval;H=widthofthemedianclass
intervalHeregivenN=230&fromtableN=f1+f2+150Givenmedian=46,thiscumulativefreqlieswithininterval(4050);N2=115,L=40;C=f1+42;f=65;H=10Therefore40+(115(f1+42)65×10)=46(11542f165×10)=4640(73f1)×10=6×6573010f1=39010f1=39073010f1=340f1=34Nowf1+f2+150=230f2=23015034f2=46

256561_236840_ans.PNG

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