An incompressible fluid is flowing in a cylindrical pipe of internal diameter 4cm with a velocity of 5m/s. If this tube is joined with another tube of internal diameter 2cm, then the velocity of flow of fluid in the smaller tube will be
A
10m/s
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B
20m/s
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C
40m/s
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D
5m/s
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Solution
The correct option is B20m/s According to equation of continuity for incompressible fluid A1V1=A2V2
Thus R12V1=R22V2(Area=πR2) 221002×5=121002×V2 V2=20m/s