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Question

An incompressible fluid is flowing in a cylindrical pipe of internal diameter 4 cm with a velocity of 5 m/s. If this tube is joined with another tube of internal diameter 2 cm, then the velocity of flow of fluid in the smaller tube will be

A
10 m/s
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B
20 m/s
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C
40 m/s
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D
5 m/s
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Solution

The correct option is B 20 m/s
According to equation of continuity for incompressible fluid
A1V1=A2V2
Thus R12V1=R22V2 (Area=πR2)
221002×5=121002×V2
V2=20 m/s

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