An incompressible liquid flows through a horizontal tube as shown in the following fig. Then the velocity v of the fluid is
1.0 m/s
If the liquid is incompressible then mass of liquid entering through left end, should be equal to mass of liquid coming out from the right end.
∴M=m1+m2⇒Av1=Av2+1.5A.v
⇒A×3=A×1.5+1.5A.v⇒v=1m/s