An incompressible liquid flows through a horizontal tube L, M, N as shown in the figure. Then the velocity ' $V$ ' of the liquid through the tube N is :

1 m s^{- 1}

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2 m s^{- 1}

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4.5 m s^{- 1}

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6 m s^{- 1}

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Solution

The correct option is D $6 m s^{- 1}$
From the equation of continuity,
$\sum A_{1} V_{1} = 0$
$\Rightarrow 2 A \times 4 = \frac{A}{2} \times 4 + A V$
$\Rightarrow 8 - 2 = V$
$\Rightarrow v = 6 m / s$

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