Question

# An incompressible liquid flows through a horizontal tube L, M, N as shown in the figure. Then the velocity '$$V$$' of the liquid through the tube N is :

A
1ms1
B
2ms1
C
4.5ms1
D
6ms1

Solution

## The correct option is D $$6ms^{-1}$$From the equation of continuity,$$\sum A_{1}V_{1}=0$$$$\Rightarrow 2A\times 4=\dfrac{A}{2}\times 4+AV$$$$\Rightarrow 8-2=V$$$$\Rightarrow v=6m/s$$Physics

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