Question

An increase in pressure required to decreases the $200$ litres volume of a liquid by $0.004\%$ in the container is

(Bulk modulus of the liquid $=2100$ MPa).

• A. $188$ kPa
• B. $8.4$ kPa
• C. $18.8$ kPa
• D. $84$ kPa

Answer 1

The correct option is D $84$ kPa

Bulk modulus (k) = $\frac{P}{\frac{△V}{V}}$

Here, k = 2100 $M{P}_a$

= $2100\times {10}^6{P}_a$

and, $\frac{△V}{V}=\frac{0.004}{100}$

$\therefore$ P = k $\times$ $\frac{△V}{V}$

= $2100\times {10}^6\times \frac{0.004}{100}$

= $84\times {10}^3{P}_a=84k{P}_a$