Question

An individual with ${}^{\prime }c{d}^{\prime }$ genes was crossed with wild type ${}^{\prime }+{+}^{\prime }.$ On test-cross of $F_1,$ the progeny was
$+c105,+d115,cd-880,++900$
Distance between the ${}^{\prime }c{d}^{\prime }$ genes?

Answer 1

Since, recombination frequency, $=\frac{No.ofrecombinations}{Totalno.ofprogeny}\times 100$

$\Rightarrow \frac{115+108}{115+105+900+880}\times 100$

$\Rightarrow 11$ map units.