Question

An individual with which of the following genotypes produces the most number of types of gametes?

• A. AaBbCcDD
• B. TtRrUuVV
• C. YyWwXxcc
• D. TtRrYyPp

Answer 1

The correct option is D TtRrYyPp

The formula to calculate the types of gametes is $2^n$ , where n = the number of heterozygous genes.
AaBbCcDD, TtRrUuVV and YyWwXxcc genotypes have heterozygous allele pairs in three genes.
According to the formula, $2^3$ = 8.
Hence, option a, b and c will produce 8 different types of gametes.
The genotype: TtRrYyPp has 4 heterozygous gene or allele pairs and hence will produce $2^4$ = 16 types of gametes.
Hence, an individual with TtRrYyPp genotype produces the highest number of gametes among the given alternatives.