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Standard XII

Physics

Kirchhoff's Voltage Law

An inductance...

Question

An inductance L and a resistance R are connected to a battery. After sometime the battery is removed but L and R remain connected in the closed circuit. The value of current will reduce to 37% of its maximum value in

RL second

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\frac{R}{L}

second

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\frac{L}{R}

second

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\frac{1}{L R}

second

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Solution

The correct option is D $\frac{L}{R}$ second
Decay of current $= i (t) = i_{0} e^{- R t / L}$

$0.37 = e^{- R t / L}$

$- R t / L = l n (0.37) = - 1$

$t = L / R s e c$

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An inductance L and a resistance R are connected to a battery. After sometime the battery is removed but L and R remain connected in the closed circuit. The value of current will reduce to 37% of its maximum value in

The correct option is D LR secondDecay of current =i(t)=i0e−Rt/L0.37=e−Rt/L−Rt/L=ln(0.37)=−1t=L/R sec

The correct option is D $\frac{L}{R}$ second
Decay of current $= i (t) = i_{0} e^{- R t / L}$

$0.37 = e^{- R t / L}$

$- R t / L = l n (0.37) = - 1$

$t = L / R s e c$