An inductance of 1 mH and a charged capacitor capacitance of 10-F are connected across each other- The resonating angular frequency of circuit is

W=1/√(L)C =1/√(10^ 3× 10 × 10^ 6) w=10^4 rad s^ 1 ...

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Standard XIII

Physics

Frequency of Oscillations in LC Circuit

An inductance...

Question

An inductance of 1 mH and a charged capacitor capacitance of 10 $μ$ F are connected across each other. The resonating angular frequency of circuit is

10^{5} r a d / s

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10^{4} r a d / s

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10^{3} r a d / s

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10^{2} r a d / s

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Solution

The correct option is B $10^{4} r a d / s$
$w = \frac{1}{\sqrt{L} C}$
$= \frac{1}{\sqrt{10^{- 3} \times 10 \times 10^{- 6}}}$
$w = 10^{4} r a d s^{- 1}$

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An inductance of 1 mH and a charged capacitor capacitance of 10μF are connected across each other. The resonating angular frequency of circuit is

The correct option is B 104 rad/sw=1√LC =1√10−3×10×10−6 w=104 rad s−1

An inductance of 1 mH and a charged capacitor capacitance of 10 $μ$ F are connected across each other. The resonating angular frequency of circuit is

The correct option is B $10^{4} r a d / s$
$w = \frac{1}{\sqrt{L} C}$
$= \frac{1}{\sqrt{10^{- 3} \times 10 \times 10^{- 6}}}$
$w = 10^{4} r a d s^{- 1}$