Question

An inductive circuit contains a resistance of $10ohms$ and an inductance of $2$ henry. If an alternating voltage of $120V$ and frequency $60Hz$ is applied to this circuit, the current in the circuit would be nearly:

• A. $0.32A$
• B. $0.80A$
• C. $0.48A$
• D. $0.16A$

Answer 1

The correct option is A $0.32A$

According to the question,

$Z=\sqrt{R^2+{\left(\omega L\right)}^2}$

$=\sqrt{{10}^2+{\left(120\pi \times 2\right)}^2}$

$=376\Omega$

$I=\frac{V}{Z}$

$=\frac{120}{376}$

$=0.3Amp$