An inductive circuit contains resistance of $10$ ohms and an inductance of $20 H$ . If an alternating current voltage of $120$ volt and frequency $60 H_{z}$ is applied to this circuit, the current would be nearly.

0.016

a m p

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0.032

a m p

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0.48

a m p

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0.80

a m p

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Solution

The correct option is A $0.016$ $a m p$
Given,
$L = 20 H$
$R = 10 Ω$
$V_{0} = 120 V$
$f = 60 H z$
$X_{L} = 2 π f L = 2 \times 3.14 \times 60 \times 20 = 7536 Ω$
Impedance of the circuit is, $Z = \sqrt{(R)^{2} + (X_{L})^{2}}$
Current in the circuit, $i = \frac{V_{0}}{Z}$
$i = \frac{120}{\sqrt{(10)^{2} + (7536)^{2}}} = 0.016 a m p$
The correct option is A.

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An inductive circuit contains resistance of 10 ohms and an inductance of 20 H. If an alternating current voltage of 120 volt and frequency 60 Hz is applied to this circuit, the current would be nearly.

The correct option is A 0.016 ampGiven,L=20HR=10ΩV0=120Vf=60HzXL=2πfL=2×3.14×60×20=7536ΩImpedance of the circuit is, Z=√(R)2+(XL)2Current in the circuit, i=V0Zi=120√(10)2+(7536)2=0.016ampThe correct option is A.

An inductive circuit contains resistance of $10$ ohms and an inductance of $20 H$ . If an alternating current voltage of $120$ volt and frequency $60 H_{z}$ is applied to this circuit, the current would be nearly.