Question

An inductive coil has a resistance of 100 When an AC signal of frequency 1000 Hz is applied to the coil, the voltage leads the current by ${45}^o$. The inductance of the coil is

• A. $\frac{1}{10\pi }$
• B. $\frac{1}{20\pi }$
• C. $\frac{1}{40\pi }$
• D. $\frac{1}{60\pi }$

Answer 1

The correct option is B $\frac{1}{20\pi }$

Given : $f=1000$ Hz

Resistance of inductive coil $X_L=100\Omega$

Thus inductance of coil $L=\frac{X_L}{2\pi f}$

$\therefore$ $L=\frac{100}{2\pi \times 1000}=\frac{1}{20\pi }$ Henry