Question

An inductor 200 Milli Henry a capacitor c and resistor 10 ohm are connected in series with 100 volt, 50 second inverse AC source if the current and voltage are in phase with each other calculate the capacitance of the capacitor

Answer 1

Dear Student,


$$\begin{gathered} \phi ={\tan }^{-1}\left(\frac{X_L-X_C}{R}\right) \\ given\phi =0 \\ or,X_L-X_C=0 \\ Thus,X_L=X_C \\ f=50Hz,L=200mH \\ or,C=\frac{1}{4{\pi }^2{f}^{2}L}=\frac{1}{4\times 3.14\times 3.14\times 50\times 50\times 200\times {10}^{-3}}\Rightarrow 507\times {10}^{-6}Fi.e507\mu F \end{gathered}$$

Regards.