wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An inductor-coil, a capacitor and an AC source of rms voltage 24 V are connected in series. When the frequency of the source is varied, a maximum rms current of 6.0 A is observed. If this inductor coil is connected to a battery of emf 12 V and internal resistance 4.0 Ω, what will be the current?

Open in App
Solution

RMS value of voltage, Erms = 24 V
Internal resistance of battery, r = 4 Ω
RMS value of current, Irms = 6 A
Reactance R is given by,
R=EIrmsR=246=4 Ω
Let R' be the total resistance of the circuit. Then,
R' = R + r
R' = 4 Ω + 4 Ω
R' = 8 Ω

Current, I = 128 A
= 1.5 A

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Maxwell's Equation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon