You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Alternating Current Applied to an Inductor

An inductor c...

Question

An inductor coil stores $U$ energy when $i$ current is passed through it and dissipates energy at the rate of $P$ . The time constant of the circuit, when this coil is connected across a battery of zero internal resistance is :

\frac{4 U}{P}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{U}{P}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2 U}{P}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{2 P}{U}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{2 U}{P}$
Energy stored in coil $U = \frac{1}{2} L I^{2}$

Power dissipated $P = I^{2} R$

From above equation $L = \frac{2 U}{I^{2}}, R = \frac{P}{I^{2}}$

we know that time constant $τ = \frac{L}{R} = \frac{2 U / I^{2}}{P / I^{2}}$

$τ = \frac{2 U}{P}$

Suggest Corrections

Similar questions

Q. An inductor coil stores

32 J

of magnetic field energy and dissipates energy as heat at the rate of

320 W

when a current of

4 A

is passed through it. Find the time constant of the circuit when this coil is joined across an ideal battery.

Q. If a battery of emf E and internal resistance

r

is connected across a load of resistance R. Show that the rate at which energy is dissipated in R is maximum when R = r and this maximum power is

P = E^{2} / 4 r

An ideal inductor is connected in series with a resistor and an ideal battery. The battery supplies energy at a rate P(t), the resistor dissipates energy at a rate $P_{R} (t)$ , and the inductor stores energy at a rate $P_{L} (t)$ . What can be concluded about the relationship between $P_{R} (t)$ and $P_{L} (t)$ ?

Q. A

20

Henry inductor coil is connected to a

10 o h m

resistance in series as shown in figure. The time at which rate of dissipation of energy (joule's heat) across resistance is equal to the rate at which magnetic energy is stored in the inductor is

Q. A

20

Henry inductor coil is connected to a

10 o h m

resistance in series as shown in figure. The time at which rate of dissipation of energy (joule's heat) across resistance is equal to the rate at which magnetic energy is stored in the inductor is

Join BYJU'S Learning Program

An inductor coil stores U energy when i current is passed through it and dissipates energy at the rate of P. The time constant of the circuit, when this coil is connected across a battery of zero internal resistance is :

The correct option is B 2UPEnergy stored in coil U=12LI2Power dissipated P=I2RFrom above equation L=2UI2,R=PI2we know that time constant τ=LR=2U/I2P/I2τ=2UP

An inductor coil stores $U$ energy when $i$ current is passed through it and dissipates energy at the rate of $P$ . The time constant of the circuit, when this coil is connected across a battery of zero internal resistance is :

The correct option is B $\frac{2 U}{P}$
Energy stored in coil $U = \frac{1}{2} L I^{2}$

Power dissipated $P = I^{2} R$

From above equation $L = \frac{2 U}{I^{2}}, R = \frac{P}{I^{2}}$

we know that time constant $τ = \frac{L}{R} = \frac{2 U / I^{2}}{P / I^{2}}$

$τ = \frac{2 U}{P}$