Question

An inductor of resistance $200\Omega$ and self inductance $1\text{H}$ is connected to an ac-source of frequency $\frac{100}{\pi }\text{Hz}$. Find out the phase difference between voltage and current in circuit.

Answer 1

$\because \omega =2\pi f=200(f=\frac{100}{\pi })$

For an LR circuit , $\tan \varphi =\frac{L\omega }{R}=1$

$\Rightarrow \varphi ={45}^{\circ }$

Hence, option (c) is the correct answer.