An industrial fuel- -water gas- which consists of a mixture of H 2 and CO can be made by passing steam over red-hot carbon- The reaction is-C s - H 2 O g - CO g - H 2 g - - H -131 kJThe yield of the product can be increased by-A- Adding of He g at constant pressureB- Adding hot carbonC- Raising the temperatureD- Reducing the volume of the system

The correct options are A Adding of He(g) at constant pressure C Raising the temperature(a) nbsp;He is an inert gas, adding inert gas at constant pressure wil ...

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Standard XII

Chemistry

Effect on Kc

An industrial...

Question

An industrial fuel, 'water gas', which consists of a mixture of $H_{2}$ and $C O$ can be made by passing steam over red-hot carbon. The reaction is:
$C (s) + H_{2} O (g) ⇌ C O (g) + H_{2} (g), Δ H = + 131 k J$
The yield of the product can be increased by:

Adding of

H e (g)

at constant pressure

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Adding hot carbon

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Raising the temperature

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Reducing the volume of the system

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Solution

The correct options are
A Adding of $H e (g)$ at constant pressure
C Raising the temperature
(a) $H e$ is an inert gas, adding inert gas at constant pressure will increase the volume of the system, which results in decrease in concentration. So according to Le Chatelier's principle, the reaction will shift in that direction where the number of gaseous moles are more. Hence, more product will be formed.
(b) Adding solids does not affect equillibrium.
(c) This is an endothermic reaction. So, the reaction will move forward on increasing temperature.
(d) Reducing volume will increase the concentration and hence reaction will move in the direction where the gaseous moles are less. Hence, in this case the reaction will move backwards.

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Similar questions

Q. Water gas, an individual fuel, consisting

C O

and

H_{2}

in equimolar amounts is obtained by passing steam over red-hot carbon in accordance with the reaction:

C (s) + H_{2} O (g) ⇌ C O (g) + H_{2} (g); Δ H = + 130.5 k J

The yield of water gas can be increased by:
(1) Reducing the total pressure of the system
(2) Increasing pressure of steam
(3) Raising the temperature
(4) Introducing hot carbon

Q. An industrial fuel, 'water gas', which consists of a mixture of

H_{2}

and CO can be made by passing steam over
red hot carbon. The reaction is :

C (s) + H_{2} O ⇌ C O (g) + H_{2} O, Δ H = + 131 k J

The yield of CO and

H_{2}

at equilibrium would be shifted to the product side by :

Q. Water gas, a mixture of

H_{2}

and CO, is an important industrial fuel produced by the reaction of steam with red hot coke, essentially pure carbon. Write the expression for the equilibrium for the equilibrium constant for the reversible reaction.

C (s) + H_{2} O (g) ⇌ C O (g) + H_{2} (g)

Δ H = 131.30

kJ.

Q. Water gas, a mixture of

H_{2}

and

C O

, is an important industrial fuel produced by the reaction of steam with red-hot coke,essentially pure carbon. Write the expression for the equilibrium constant for the reversible reaction.

C (s) + H_{2} O (g) ⇌ C O (g) + H_{2} (g) Δ H = 131.30 k J

Q. For the reaction

C O (g) + H_{2} O (g) ⇌ C O_{2} (g) + H_{2} (g)

at a given temeprature, the equilibrium amount of

C O_{2} (g)

can be increased by:

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An industrial fuel, 'water gas', which consists of a mixture of H2 and CO can be made by passing steam over red-hot carbon. The reaction is: C(s)+H2O(g)⇌CO(g)+H2(g), ΔH= +131 kJ The yield of the product can be increased by:

An industrial fuel, 'water gas', which consists of a mixture of $H_{2}$ and $C O$ can be made by passing steam over red-hot carbon. The reaction is:
$C (s) + H_{2} O (g) ⇌ C O (g) + H_{2} (g), Δ H = + 131 k J$
The yield of the product can be increased by: