Question

An industrial heat pump working between temperature limits of ${30}^{o}C$ and $-{10}^C$. The cycle takes $750W$ of heat and rejects $1000W$. What will be the COP for the heat pump?

• A. $6.575$
• B. $4$
• C. $3$
• D. $7.575$

Answer 1

The correct option is B $4$



$COP=\frac{Q_2}{Q_1-Q_2}$

$COP=\frac{1000}{1000-750}=4$

NNote: $COP=\frac{T_2}{T_1-T_2}$

This is for maximum (Carnot) COP.