An infinite number of identical point masses each equal to m are placed at point x=1,x=2,x=4,x=8,........... The total gravitational potential at point x=0 is
A
−Gm
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B
−2Gm
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C
+2Gm
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D
infinite
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Solution
The correct option is B−2Gm Let the point masses be p1,p2,p3......pa.................(a>0,aisinteger) Now potential at x=0 due to p1 be P1=−GM1 Similarly P2=−GM2, P3=−GM4,........ So, total potential is given by P=P1+P2+P3+......... P=−GM1+−GM2+−GM4+−GM8+................ P=−GM(1+12+14+18+................) This is a sum of infinite terms with common ratio 12. Therefore,P=(−GM)1(1−12)=−2GM.