An infinite number of tangents can be drawn from (1,2) to the circle x2+y2−2x−4y+λ=0. Then
An infinite number of tangents can be drawn from (1, 2) to the circle x2+y2−2x−4y+λ=0, then λ=
The circle x2+y2−6x−4y+9=0 bisects the circumference of the circle x2+y2−(λ+4)x−(λ+2)y+(5λ+3)=0 if λ is equal to