An infinite thread of charge density $λ$ lies along z-axis. The potential difference between points A(4, 3, 4) and B(3, 4, 0) is

\frac{λ}{2 π l_{0}} I n (\frac{\sqrt{41}}{5})

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\frac{λ}{2 π l_{0}} I n (5)

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z e r o

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\frac{λ}{2 π l_{0}}

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Solution

The correct option is C $z e r o$
Equipotential surfaces are coaxial cylinders, therefore (4, 3, 4) and (3, 4, 0) lie on equipotential surface.

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An infinite thread of charge density λ lies along z-axis. The potential difference between points A(4, 3, 4) and B(3, 4, 0) is

The correct option is C zeroEquipotential surfaces are coaxial cylinders, therefore (4, 3, 4) and (3, 4, 0) lie on equipotential surface.

An infinite thread of charge density $λ$ lies along z-axis. The potential difference between points A(4, 3, 4) and B(3, 4, 0) is

The correct option is C $z e r o$
Equipotential surfaces are coaxial cylinders, therefore (4, 3, 4) and (3, 4, 0) lie on equipotential surface.