An infinitely long current carrying wire and a small current carrying loop are in the plane of the paper as shown. The radius of the loop is a and the distance of its centre from the wire is d(d>>a). If the loop applies a force F on the wire, then:
A
F∝(a2d3)
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B
F=0
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C
F∝(ad)
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D
F∝(ad)2
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Solution
The correct option is DF∝(ad)2 The circular loop can be considered as a magnetic dipole.
Therefore, Force on dipole,
F=m.dBdr
m→magnetic moment
The magnetic field due to the long current carrying wire is given by,
B=μ0i2πr
⇒dBdr=−μ0i2πr2
Magnetic moment,m=Iπa2
⇒|F|=Iπa2×μ0i2πr2
⇒F∝a2r2
Here,r=d
⇒F∝a2d2
Note: By Newton's third law, the same force is exerted by the loop on the wire.