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Question

An infinitely long current carrying wire and a small current carrying loop are in the plane of the paper as shown. The radius of the loop is a and the distance of its centre from the wire is d (d>>a). If the loop applies a force F on the wire, then:


A
F(a2d3)
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B
F=0
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C
F(ad)
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D
F(ad)2
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Solution

The correct option is D F(ad)2
The circular loop can be considered as a magnetic dipole.

Therefore, Force on dipole,

F=m.dBdr

mmagnetic moment

The magnetic field due to the long current carrying wire is given by,

B=μ0i2πr

dBdr=μ0i2πr2

Magnetic moment, m=Iπa2

|F|=Iπa2×μ0i2πr2

Fa2r2

Here, r=d

Fa2d2

Note: By Newton's third law, the same force is exerted by the loop on the wire.

Hence, option (D) is correct.

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