An infinitely long current carrying wire and a small current carrying loop are in the plane of the paper as shown. The radius of the loop is a and distance of its centre from the wire is d(d>>a). If the loop applies a force F on the wire then
A
F∝(a2d3)
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B
F∝(ad)2
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C
F∝(ad)
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D
F=0
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Solution
The correct option is BF∝(ad)2 The circular loop will behave as a magnetic dipole with upper face as north pole .
Equivalent diagram of the question from top view
Force on the dipole placed in a non-uniform magnetic field is given by
F=MdBdx
(M=magnetic moment of the coil)
F=iπa2(ddx(μ0i2πx))
[magnetic moment = i×area]
field B due to wire at distance x from wire =μ0i2πx
F=iπa2(μ0i2π)(−1x2)
F∝a2x2⇒F∝a2d2
(here x=d= distance of loop from wire )
Force by loop on wire will be equal and opposite to the force on loop by wire (Newton's 3rd law action reaction pair )