Question

An infinitely long cylinder of radius $R=2cm$ carries a uniform charge density $=18\mu C/m^3.$

Calculate the electric field at distance $r=1cm$

from the axis of the cylinder.

• A. The magnitude of electric field intensity at the xx axis of charged body is $\left(\frac{p{r}^2}{2{\in }_{0}d}\right)$
• B. The magnitude of electric field intensity at the xx axis of charged body is zero.
• C. The magnitude of electric field intensity at the yy axis of charged body is $\left(\frac{p{d}^2}{2{\in }_0}\right)$
• D. The magnitude of electric field intensity at the xx any point in the cavity is $\frac{p^2}{2{\in }_0}d$

Answer 1

The correct option is A The magnitude of electric field intensity at the xx axis of charged body is $\left(\frac{p{r}^2}{2{\in }_{0}d}\right)$

Magnitude of $E.ds=\frac{q_{rms}}{{ϵ}_0}$

$Q_E=AE$

Combining this and we get, $\frac{{\rho r}^2}{2{ϵ}_{0}d}$.