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Question

An inorganic compound (A) shows the following reactions

i) It is white solid exists as dimmer and gives fumes of (B) with wet air

ii) It sublimes in 180C and form monomer If heated to 400C

iii) Its aq solution turns blue litmus to red.

iv) Addition of NH4OH and NaOH separately to a solution of (A) gives white ppt

which is however soluble in excess of NaOH. What is 'A'


A

Al2Cl6

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B

NH4OH

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C

Al (OH)3

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D

NaOH

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Solution

The correct option is A

Al2Cl6


'A' is the white solid existing as dimmer

A may be AlCl3 existing as Al2Cl6 (White)

i) When Al2Cl6 is exposed to moist air

Al2Cl6+6H2O2AI(OH)3+6HCl

(fumes of HCl and colloidal Al(OH)3

ii) when (A) is heated to 180C it sublimes to give

Al2Cl6180C−−Al2Cl6(g) and when heated to 400C it gives monomer

Al2Cl6400C−−2AlCl3

iii) When heated with NH_4OH and NaOH separately give

Al2Cl6+6NH4OH2Al(OH)36NH4Cl

(whiteppt)

and Al2Cl6+6NaOH2Al(OH)36NaCl

(whiteppt)

again Al(OH)3+NaOHNaAlO2+2H2O

(excess)(Soluble)


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